Home
Class 12
CHEMISTRY
In a crystal structure oxide ion forms C...

In a crystal structure oxide ion forms CCP . `A^(2+)` ion occupy one of the octahedral voids and `B^(3+)` ions are equally distributed between tetrahedral and octahedral voids.If `(1)/(8)` th of the tetrahedral voids are occupied by `B^(3+)` ion and sum of % occupancy of `B^(3+)` ion in octahedral and tetrahedral voids is `(x)/(2)` then the value of x is

Promotional Banner

Similar Questions

Explore conceptually related problems

In a compound XY_(2) O_(4) , oxide ions are arranged in CCP and cations X are present in octahedral voids. Cations Y are equally distributed between octahedral and tetrahedral voids. The fraction of the octahedral voids occupied is :-

In a crystalline solid, anions Y are arranged in ccp arrangement. Cations 'X' are equally distributed between tetrahedral and Octahedral voids. If all the octahedral voids are occupied, what is the formula of solid ?

In a crystalline solid, anions B are arranged in a ccp. Cations A are equally distributed between octahedral and tetrahedral voids. If all the octahedral voids are occupied, the formula of the compound is A_2B//A_3B .

In Zinc blende , the percentage of tetrahedral voids occupied by Zn^(2+) ions is :

In a crystalline solid, anions Y^(-) are arranged in ccp. Cation X^(+) are equally distributed between octehedral and tetrahedral voids. If all the octahedral voids are occupied, what is the formula of the compound ?

In a crystalline solid, anions B are arranged in ccp structure. Cations A are equally distributed between octahedral and tetrahedral voids if all the octahedral voids are occupied the formula of the ionic solids will be

In a crystalline solid anions B are arranged in cubic close packing. Cation A are equally distributed between octahedral and tetrahedral voids. If all the octahedral voids are occupied, the formula for the solid is

A forms ccp lattice B occupy half of the octahedral voids and O occupy all the tetrahedral voids. Calculate formula-