The velocity of water in a river is `2ms ` at the surface.If the river is `2m` deep the shearing stress between the horizontal layers of water assuming bottom layer at rest (`eta=10^(-3) S I` units for water)

The velocity of water in a river is 18 kmph near the surface. If the river is 4 m deep, the shearing stress between horizontal layers of water in Nm^(-2) is (eta_("water")=1xx10^(-3)pa.s)

The velocity of water in a river is 72 km h^(-1) near the surface. If the river is 4 m deep, find the shearing stress between horizontal layers of water. Coefficient of viscosity of water = 0.01 poise.

The velocity of water in a rier is 18kmh^-1 near the surface. If the river is 5 m deepm, find the shearing stress between the horizontal lyers of water. The coefficient of viscosity of water =10^-2 poise.

The velocity of water in a river is 18 km/h near the upper surface. The river 5 m deep. What is the shearing stress between the horizontal layers of water ? (Coefficient of viscosity of water= 10^(- 2) Poise)

The velocity of water in river is 180 km h^(-1) near the surface .If the river is 5 m deep,then the shearing stress between the surface layer and the bottom layer is ( cofficient of viscosity of water eta =10^(-3) Pa s)

A river 10 m deep is flowing at 5ms^(-1) . The shearing stress between horizontal layers of the rivers is ( eta=10^-(3) SI units)

The velocity of water near a river's surface is 20 km/hr. If the depth of the river is 4 m, calculate the shearing stress between the horizontal layers of water. Take, coefficient of viscosity of water = 0.01 poise.

If the shearing stress between the horizontal layers of water in a river is 1.5 milli "newton"//m^(2) and eta_("water")=1xx10^(-3)Pa.s The velocity gradient is … s^(-1)

The velocity of water in river is 9 km/h of the upper surface . The river is 10 m deep . If the coefficient of viscosity of water is 10^(-2) poise then the shearing stress between horizontal layers of water is

We know that when a boat travels in water, its net velocity w.r.t. ground is the vector sum of two velocities. First is the velocity of boat itself in river and other is the velocity of water w.r.t. ground. Mathematically: vecv_(boat) = vecv_(boat,water) + vecv_(water) . Now given that velocity of water w.r.t. ground in a river is u. Width of the river is d. A boat starting from rest aims perpendicular to the river with an acceleration of a = 5t, where t is time. The boat starts from point (1,0) of the coordinate system as shown in figure. Assume SI units.