`int_(pi/6)^( pi/2)(cos x)/(sin^(2)x)dx`

int_(pi//6)^(pi//2) cos x dx

int_(0)^( pi/2)|cos x-sin x|dx

int_(0)^( pi)(sin x)/(1+cos^(2)x)dx =

int_(-pi//2)^(pi//2)(sin^(4)x)/(sin^(4)x + cos^(4)x)dx=

int_(-pi/2)^(pi/2)(a cos^(2)x+b sin^(2)x)dx

If A = int_(0)^((pi)/(2))(sin^(3)x)/(1+cos^(2)s)dx and B=int_(0)^((pi)/(2))(cos^(2)x)/(1+sin^(2)x)dx , then (2A)/(B) is equal to

Evaluate int_(-pi/2)^(pi/2)(sin2x)/(1+cos^3x)dx

u,=int_(0)^((pi)/(2))cos((2 pi)/(3)sin^(2)x)dx and v,=int_(0)^((pi)/(2))cos((pi)/(3)sin x)dx

If A=int_(0)^( pi)(cos x)/((x+2)^(2))dx, then int_(0)^( pi/2)(sin2x)/(x+1)dx is equal to