`(3) int dx/cos^2x`

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" (3) "int(dx)/(cos^(2)x)

int(dx)/(3+2cos^(2)x)

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int(dx)/(3-2cos2x)=

int(dx)/(3cos2x+5)=

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int e^x cos 2x dx

int x^(3)*cos x^(2)dx

int cos x cos3x*dx

Evaluate : (i) int(dx)/((1+3sin^(2)x)) (ii) int(dx)/((3+2cos^(2)x))