Two particle of mass 4 kg & 2kg are located as shown in figure then find out the position of centre of mass.

Options

A. `4/3` , 1
B. 1 , `4/3`
C. 0 , 0
D. 4 , 3

Answer

A

Explanation

First find out the position of 2 kg mass
`x_(2kg)=5cos37^(@)=4m`
`y_(2kg)=5sin37^(@)=3m`
So these system is like two particle system of mass 4 kg and 2kg are located (0, 0) and (4, 3) respectively. Then
`x_("com")=(m_(1)x_(1)+m_(2)x_(2))/(m_(1)+m_(2))=(0+2xx4)/(4+2)=8/6=4/3`
`y_("com")=(m_(1)y_(1)+m_(2)y_(2))/(m_(1)+m_(2))=(0+3xx2)/(4+2)=1m`

So position of C.O.M is `(4/3,1)`