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A body performs simple harmonic oscillat...

A body performs simple harmonic oscillations along the straight line `ABCDE` with `C` as the midpoint of `AE`. Its kinetic energies at `B` and `D` are each one fourth of its maximum value. If `AE = 2R`, the distance between `B` and `D` is

A

`(sqrt(3)R)/(2)`

B

`( R)/(sqrt(2))`

C

`sqrt(3)` R

D

`sqrt(2)` R

Text Solution

Verified by Experts

The correct Answer is:
C
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