Home
Class 12
PHYSICS
Speed v of a particle moving along a str...

Speed `v` of a particle moving along a straight line, when it is a distance X from a fixed point on the line is given by `V^(2)=108-9X^(2)` (all quantities in S.I. unit). Then

A

The motion is uniformly accelerated along the straight line

B

The magnitude of the acceleration at a distance 3 cm from the fixed point is 0.27 m/`s^(2)`.

C

The motion is simple harmonic about x = `sqrt(12)` m.

D

The maximum displacement from the fixed point is 4 cm

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARONIC MOTION

    MOTION|Exercise EXERCISE -2 (Leve-I) ( SECTION - B ) ( Time per iod and angu larfrequency in SHM )|7 Videos
  • SIMPLE HARONIC MOTION

    MOTION|Exercise EXERCISE -2 (Leve-I) ( SECTION - C ) ( Two block system )|5 Videos
  • SIMPLE HARONIC MOTION

    MOTION|Exercise EXERCISE -1 ( SECTION - H ) ( Combination of two or more SHM )|4 Videos
  • SIMPLE HARMONIC MOTION

    MOTION|Exercise EXERCISE -3 Section - B Previous Year Problems | JEE MAIN|23 Videos
  • SOUND WAVES

    MOTION|Exercise Exercise - 3 (Section - B)|14 Videos

Similar Questions

Explore conceptually related problems

The speed v of a particle moving along a straight line, when it is at a distance (x) from a fixed point of the line is given by v^2=108-9x^2 (all equation are in CGS units):

The speed (v) of particle moving along a straight line, when it is of a distance (x) from a fixed point on the line, is given by : v^(2) = 144 - 9x^(2)

The speed v of a particle moving along a straight line. When it is at distance x from a fixed point on the line is v^(2)=144-9x^(2) . Select the correct alternatives

A particle moves in a straight line, so that after t second, the distance x from a fixed point O on the line is given by x=(l-2)^(2)(t-5) . Then

If the velocity v of a particle moving along a straight line and its distance s from a fixed point on the line are related by v^(2)=a^(2)+s^(2) , then its acceleration equals

A particle is moving on a straight line and its distance x cms from a fixed point O on the line is given by x=sqrt(t^(2)+1) then the velocity of particle at t=1 is

If a particle moving in a straight line and its distance x cms from a fixed point O on the line is given by x=sqrt(1+t^(2)) cms, then acceleration of the particle at t sec. is

If a particle is moving along straight line with increasing speed, then

A particle is moving along a straight line with increasing speed. Its angular momentum about a fixed point on this line :

The law of motion of a body moving along a straight line is x=1/2vt , x being its distance from a fixed point on the line at time t and v is its velocity there. Then