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A body at the end of a spring executes S...

A body at the end of a spring executes SHM with a period `t_(1),` while the corresponding period for another spring is `t_(2),` If the period of oscillation with the two spring in series is T, then

A

`T = t_(1)+t_(2)`

B

`T^(2) = t_(1)^(2)+t_(2)^(2)`

C

`(1)/(T)=(1)/(t_(1))+(1)/(t_(2))`

D

`(1)/(T^(2))=(1)/(t_(1)^(2)) + (1)/(t_(2)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • A particle at the end of a spring executes simple harmonic motion with a period t_(1) while the corresponding period for another spring is t_(2) if the oscillation with the two springs in series is T then

    A
    `T^(2) =t_(1)^(2)+t_(2)^(2)`
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    `T= t_(1)+t_(2)`
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    `T^(-1)=t_(1)^(-1)+t_(2)^(-1)`
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    `T^(-2)=t_(1)^(-2)+t_(2)^(-2)`
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    (a) `T^(-1)=t_(1)^(1)+t_(2)^(-1)`
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    (b) `T^(2)=t_(1)^(2)+t_(2)^(2)`
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    B
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