A pendulum suspended from the roof of an elevator at rest has a time period `T_(1)`, when the elevator moves up with an acceleration `a` its time period becomes `T_(2)`, when the elevator moves down with an acceleration `a`, its time period becomes `T_(3)`, then

Options

A. `T_(3) gt T_(2) "and " T_(1)`
B. `T_(2) gt T_(3) gt T_(1)`
C. `T_(1) = (T_(2)T_(3)sqrt(2))/(sqrt((T_(2)^(2)+T_(3)^(2))))`
D. `T_(2)=sqrt(T_(2)^(2)+T_(3)^(2))`

Answer

A, C