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A force F=-10x+2 acts on a particle of m...

A force F=-10x+2 acts on a particle of mass 0.1 kg where m is m and F is in newtons. If F is released from rest at x=0, find:
a. amplitude:
b. time period:
c. equation of motion.

Text Solution

Verified by Experts

(a) `(11)/(5)` m (b) `(pi)/(5)` sec ( c) `x= 0.2 - (11)/(5) "cos" omega t `
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