Home
Class 12
PHYSICS
A point particle of mass 0.1kg is execut...

A point particle of mass `0.1kg` is executing `SHM` with amplitude of `0.1m`. When the particle passes through the mean position. Its `K.E.` is `8xx10^(-3)J`. Obtain the equation of motion of this particle if the initial phase of oscillation is `45^(@)`.

Text Solution

Verified by Experts

The correct Answer is:
y = 0.1 sin (4t +`pi`/4)
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARONIC MOTION

    MOTION|Exercise EXERCISE -3 (Leve-II) ( SECTION -B ) (Time per iod and angu larfrequency in SHM)|3 Videos

  • SIMPLE HARONIC MOTION

    MOTION|Exercise EXERCISE -3 (Leve-II) ( SECTION -C ) (Two block system)|2 Videos

  • SIMPLE HARONIC MOTION

    MOTION|Exercise EXERCISE -3 (Leve-I) ( SECTION -H ) (Combination of two or more SHM )|3 Videos

  • SIMPLE HARMONIC MOTION

    MOTION|Exercise EXERCISE -3 Section - B Previous Year Problems | JEE MAIN|23 Videos

  • SOUND WAVES

    MOTION|Exercise Exercise - 3 (Section - B)|14 Videos

Similar Questions

Explore conceptually related problems

A point particle of mass 0.1kg is executing SHM of amplitude 0.1m . When the particle passes through the mean position, its kinetic energy is 8xx10^-3J . Obtain the equation of motion of this particle if the initial phase of oscillation is 45^@ .

A point particle of mass 0.1 kg is executing SHM of amplitude 0.1m. When the particle passes through the mean position, its kinetic energy is 8xx10^(-3)J . Obtain the equation of motion of the particle if the initial phase of oscillation is 45^(@)

A point particle if mass 0.1 kg is executing SHM of amplitude 0.1 m . When the particle passes through the mean position, its kinetic energy is 8 xx 10^(-3)J . Write down the equation of motion of this particle when the initial phase of oscillation is 45^(@) .

A particle of mass 0.2 kg is excuting SHM of amplitude 0.2 m. When it passes through the mean position its kinetic energy is 64 xx 10^(-3) J . Obtain the equation of motion of this particle if the initial phase of oscillation is pi//4 .

A particle of mass 100 g is executing S.H.M. with amplitude of 10 cm. When the particle passes through the mean position at t = 0. Its kinetic energy is 8 mJ. The equation of simple harmonic motion, if initial phase is zero is

In the equation of motion of a particle y = 0.5 sin (0.3t + 0.1) , the initial phase of motion is -

A body is executing SHM with an amplitude of 0.1 m. Its velocity while passing through the mean position is 3ms^(-1) . Its frequency in Hz is

A body of mass 0.1 kg is executing a simple harmonic motion of amplitude 0.2 m. When the body passes through the mean position, its kinetic energy is 8xx10^(-3) J. The initial phase of oscillation is 60. What is the equation of motion of the body ?