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In a insulated vessel, 0.05 kg steam at 373 K and 0.45 kg of ice at 253 K are mixed. Find the final temperature of the mixture (in kelvin.)
Given, `L_(fusion) = 80 cal//g = 336 J//g`
`L_("vaporization") = 540 cal//g = 2268 J//g`
`s_(ice) = 2100 J//kg.K = 0.5 cal//g.K`
and `s_("water") = 4200 J//kg.K = 1cal//g.K` .

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0.05 kg steam at 373K and 0.45kg of ice at 253K are mixed in an insultated vessel. Find the equilibrium temperature of the mixture. Given, L_(fusion)=80cal//g=336J//g, L_(vaporization)=540 cal//g=2268J//g,C_(ice)=2100J//KgK=0.5calg//gK and S_(water)=4200J//KgK=1cal//gK

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1 g of steam at 100^@C and an equal mass of ice at 0^@C are mixed. The temperature of the mixture in steady state will be (latent heat of steam =540 cal//g , latent heat of ice =80 cal//g ,specific heat of water =1 cal//g^@C )

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