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A wire of length 1m and area of cross se...

A wire of length 1m and area of cross section `4 xx 10^(-8) m^(2)` increases in length by 0.2 cm when a force of 16 N is applied. Value of Y for the material of the wire will be

A

`2xx10^(6)" N/m"^(2)`

B

`2xx10^(11)" kg/m"^(2)`

C

`2xx10^(11)" N/mm"^(2)`

D

`2xx10^(11)" N/m"^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
By Hook's law
`Y=(F//A)/(l//L)=(FL)/(Al)`
`Y =(16xx1)/((4xx10^(-8))(0.2xx10^(-2)))=2xx10^(11) N//m^(2)`
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