A faulty thermometer reads `5^(@)` at freezing point and `95^(@)` at boiling point then findout original reading in `""^(@)C` when it reads `50^(@)`.

Explanation

`(50-5)/(95-5) =(x-0)/(100) rArr (45)/(90) =(x)/(100) rArr x=50`
Effect of temperature of Buoyancy Force Initially at temperature T
`F_(B) = v rho_(1) g`
on increase temperature at `Delta T` then

`F_(B) =(V(1+gamma_(B) Delta T)rho_(t)g)/((1+gamma_(l)Delta T))=v rho_(l)g""((1+gamma_(B) Delta T))/((1+gamma_(l) Delta T))`
(a) If `gamma_(B) gt gamma_(L) & T uarr" then "F_(B) darr`

(b) If `gamma_(L) gt gamma_(B) & T uarr" then "F_(B) darr, and T darr`