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Monochromatic light of wavelength 5000 Å...

Monochromatic light of wavelength 5000 Å is used in Y.D.S.E., with slit-width, d = 1mm, distance between screen and slits, D = 1m. If intensity at the two slits are `I_(1)=4I_(0), I_(2)=I_(0)`, find
Distance of the `1000^(th)` maxima

Text Solution

Verified by Experts

`(d)/(lambda)=(10^(-3))/(0.5xx10^(-6))=2000`
n = 1000 is not `lt lt 2000`
Hence now `Delta p = d sin theta` must be used
Hence, `d sin theta = n lambda = 1000 lambda`
`rArr sin theta = 1000 (lambda)/(d)=(1)/(2)`
`rArr theta = 30^(@)`
`y = D tan theta =(1)/(sqrt(3))` meter
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Monochromatic light of wavelength 5000 Å is used in Y.D.S.E., with slit-width, d = 1mm, distance between screen and slits, D = 1m. If intensity at the two slits are I_(1)=4I_(0), I_(2)=I_(0) , find fringe width beta

Monochromatic light of wavelength 5000 Å is used in Y.D.S.E., with slit-width, d = 1mm, distance between screen and slits, D = 1m. If intensity at the two slits are I_(1)=4I_(0), I_(2)=I_(0) , find distance of 5th minima from the central maxima on the screen

Knowledge Check

  • Light of wavelength lambda is incident on a slit of width d and distance between screen and slit is D. Then width of maxima and width of slit will be equal if D is ––

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