In a biprism experiment , the slit is illuminated with light of wavelength `4800 Å` . The distance the slit and birprism is 20cm and that between biprism and eyepiece is 80cm . If two virtual source are 0.3 cm apart, determine the distance between the 5th bright band on one side of the central bright band and the 5th dark bank on the other side.

Explanation

Here `lambda = 4.8xx10^(-7)m, d=0.3 xx10^(-2)m`,
`D=20+80=100cm = 1m`
Distance of 5th bright from the central bright band is
`x_(5)=5(Delta lambda)/(d)`