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In Young's double slit experiment, the m...

In Young's double slit experiment, the maximum intensity is `I_(0)`. What is the intensity at a point on the screen where the path difference between the interfering waves is `lamda/4` ?

A

`sin^(-1)((lambda)/(d))`

B

`sin^(-1)((lambda)/(3d))`

C

`sin^(-1)((lambda)/(2d))`

D

`sin^(-1)((lambda)/(4d))`

Text Solution

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The correct Answer is:
B
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MOTION-WAVE OPTICS -EXERCISE - 4 (Level - II) Previous Year | JEE Main
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