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Using the expression 2d sin theta = lamb...

Using the expression `2d sin theta = lambda`, one calculates the values of `d` by measuring the corresponding angles `theta` in the range `0 to 90@`. The wavelength `lambda` is exactly known and error in `theta` is constant for all values of `theta`. As `theta` increases from `0@`

A

the absolute error in d remains constant

B

the absolute in d increases

C

the fractional error in d remains constant

D

the fractional error in d decreases

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The correct Answer is:
D
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