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Binding energy per nucleon of .1H^2 and ...

Binding energy per nucleon of `._1H^2` and `._2He^4` are 1.1 MeV and 7.0 MeV respectively. Energy released in the process `._1H^2 + ._1H^2 = ._2He^4` is -

A

20.8 MeC

B

16.6 MeV

C

25.2 MeV

D

23.6 MeV

Text Solution

Verified by Experts

The correct Answer is:
D
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