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Th^228emits an alpha particle to reduce ...

`Th^228`emits an alpha particle to reduce to `Ra^224`.Calculate the kinetic energy of the alpha particle emitted in the following decay:
`Th^228 rarr Ra^**+ alpha`
`(Ra^224)^** rarr Ra^224+ gamma(217 keV)`
Atomic mass of `Th^228` is `228.028726 u`,that of `Ra^224`is `224.020196 u` and that of `He_2^4` is `4.00260 u.`

Text Solution

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The correct Answer is:
5.304 MeV
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