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A nucleus of mass M + Deltam is at rest ...

A nucleus of mass `M + Deltam` is at rest and decays into two daughter nuclei of equal mass M/2 each. Speed of light is C.
The speed of daughter nuclei is

A

`c(Deltam)/(M + Delta m)`

B

`csqrt((2Deltam)/(M)`

C

`csqrt((Deltam)/(M))`

D

`csqrt((Deltam)/(M+Delta m)`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • A nucleus of mass M + Deltam is at rest and decays into two daughter nuclei of equal mass M/2 each. Speed of light is C. The speed of deughter nuclei is :-

    A
    `csqrt((Deltam)/(M+mDeltam))`
    B
    `c(Deltam)/(M+Deltam)`
    C
    `csqrt((2Deltam)/(M))`
    D
    `csqrt((Deltam)/(M))`

  • A nucleus of mass M + m is at rest and decays cinto two daughter nuclei of equal mass (M ) /(2 ) each. Speed of light is C. The speed of daughter nuclei is

    A
    `c sqrt((Delta M)/( M + Delta m))`
    B
    `e (Delta m)/( M + Delta m)`
    C
    `c sqrt((2 Delta M )/( M ))`
    D
    `c sqrt( (Delta m)/( M ))`

  • A nucleus of mass M + Deltam is at rest and decays into two daughter nuclei of equal mass M/2 each. Speed of light is C. The binding energy per nucleon for the parent nucleus is E_1 and that for the daughter nuclei is E_2 . Then

    A
    `E_2 = 2E_1`
    B
    `E_1 gt E_2`
    C
    `E_2 gt E_1`
    D
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