The decomposition of dimethyl ether leads to the formation of `CH_(4),H_(2),` and `CO` and the reaction rate is given by Rate `=k[CH_(3)OCH_(3)]^(3//2)` The rate of reaction is followed by increase in the pressure in a closed vessel , so the rate can also be expressed in terms of the partial pressure of dimethyl either, `i.e., ` Rate `=k[p_(CH_(3)OCH_(3))]^(3//2)` If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constant ?
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If pressure is measured in bar and time in minutes , then Unit of rate = bar `"min"^(-1)` Rate = `k(P_(CH_(3) OCH_(3)))^((3)/(2))` `implies k = ("Rate")/((P_(CH_(3)OCH_(3)))^((3)/(2)))` Therefore , unit of rate constants `(k) = ("bar min"^(-1))/("bar"^((3)/(2)))` = `"bar"^((-1)/(2)) "min"^(-1)`
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The decomposition of dimethyl ether leads to the formation of CH_(4) , H_(2) and CO and the reaction rate is given by the expression: rate = k[CH_(3)COOH_(3)]l^(3//2) The rate of reaction is followed by increase in pressure in a close vessel and the rate can also be expressed in terms of partial pressure of dimethyl ether: rate = k[CH_(3)OCH_(3)]^(3//2) The rate of reaction is followed by increase in a close vessel and the rate can also be expressed in terms of partial pressure of dimethyl ether: rate = k[pCH_(3)OCH_(3)]^(3//2) If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constant?
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