The rate constant for the first order reaction is `60 s^(-1)`. How much time will it take to reduce the concentration of the reactant to `1//16th` value ?
Text Solution
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It is known that `t = (2.303)/(k) "log" ([R]_(0))/([R])` = `(2.303)/(60 s^(-1)) "log" (1)/((1)/(16))` =`(2.303)/(60 s^(-1)) "log" 16` = `4.6 xx 10^(-2) s` (approximately) Hence , the required time is `4.6 xx 10^(-2)s`
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