Arrange the compounds of each set in order of reactivity towards `S_(N)2` displacement:
(i) 2-Bromo-2-methylbutane, 1-Bromopentane, 2-Bromopentane
(ii) 1-Bromo-3-methylbutane, 2-Bromo-2-methylbutane, 2-Bromo-3-methylbutane
(iii) 1-Bromobutane, 1-Bromo-2,2-dimethylpropane, 1-Bromo-2-methylbutane, 1-Bromo-3-methylbutane.

Explanation

To arrange the compounds in order of reactivity towards \( S_N2 \) displacement, we need to consider the steric hindrance around the carbon atom that is bonded to the halogen. The more crowded the carbon is, the less reactive it will be towards \( S_N2 \) reactions.

### Step-by-Step Solution:

#### (i) 2-Bromo-2-methylbutane, 1-Bromopentane, 2-Bromopentane

1. **Identify the structure and steric hindrance**:
- **2-Bromo-2-methylbutane**: The bromine is attached to a tertiary carbon (C with three alkyl groups attached). This has high steric hindrance.
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