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The ratio of binding energy of a satel...

The ratio of binding energy of a satellite at rest on earth's surface to the binding energy of a satellite of same mass revolving around of the earth at a height h above the earth's surface is (R = radius of the earth).

A

`(2(R + h))/(R )`

B

`(R + h)/(2R)`

C

`(R + h)/(R )`

D

`R/(R + h)`

Text Solution

Verified by Experts

The correct Answer is:
A

Binding energy of a satellite at rest on earth’s surface Total energy K.E. + P.E
K.E. of rotation = 0
`P. E. = - (GMm)/(R ) :. " "` Binding energy of a satellite revolving around the earth at a height ‘h’
`K.E = (GMm)/(2(R + h))`
`P. E. = - (GmM)/(2(R + h))`
Total energy = `K. E. + P. E = - (GMm)/(2(R + h)) or (B.E_1)/(B. E_2) = (2(R + h))/(R)`
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