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The stopping potential for photoelectron...

The stopping potential for photoelectrons from a metal surface is `V_(1)` when monochromatic light of frequency `upsilon_(1)` is incident on it. The stopping potential becomes `V_(2)` when monochromatic light of another frequency is incident on the same metal surface. If h be the Planck’s constant and e be the charge of an electron, then the frequency of light in the second case is:

A

`upsilon_(1) - e/h (V_2 + V_1)`

B

`upsilon_(1) + e/h (V_2 + V_1)`

C

`upsilon_(1) - e/h (V_2 - V_1)`

D

`upsilon_(1) + e/h (V_2 - V_1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`eV_(1) = h upsilon_(1) - phi_(0)" "`……(i)
`wV_(2) = h upsilon_(2) - phi_(0)" "……(ii)`
Subtract (i) from (ii) , we get `eV_2 - eV_1 = h upsilon_2 - h upsilon_2 or v_2 = v_1 + e/h (V_2 - V_1)`.
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