According to molecular orbital theory, which of the following is true with respect to `C_(2)^(2+)` and `C_(2)^(2-)` ?

Options

A. Both have same number of `sigma` bonds
B. `C_(2)^(2+)` has more number of `pi` bonds and `C_(2)^(2-)` has less number of `pi` bonds
C. `C_(2)^(2+)` is paramagnetic and `C_(2)^(2-)`is diamagnetic
D. Both have same number of `pi`bonds

Answer

C

Explanation

`C_(2)^(2+) implies sigma_(1s)^(2),sigma_(1s)^(**2),sigma_(2s)^(2),sigma_(2s)^(**2), pi_(2Px)^(1), pi_(2Py)^(1)" "`(Paramagnetic)
Number of `sigma` bond = `(N_(sigma)- N_(sigma)^(**))/(2) = (4 - 4)/2 = 0`
Number of `pi` bond `= (Npi - Npi^(**))/(2) = (2- 0)/(2) = 1`
`C_(2)^(2-) implies sigma_(1s)^(2),sigma_(1s)^(**2),sigma_(2s)^(2),sigma_(2s)^(**2), pi_(2Px)^(2), pi_(2Py)^(2), sigma_(2Pz)^2" "`(Diamagnetic)
Number of `sigma` bond = `(6-4)/2 = 1`, Number of `pi` bond = `(4-2)/2 = 2`.