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If y = y(x) is the solution of the diff...

If `y = y(x)` is the solution of the differential equation,`x (dy)/(dx) + 5y = 10x^5, x > 0` satisfying `y(1) = 2` then range of `y(x)` for `x > 0` is:

A

`[1,oo)`

B

`[2 , oo)`

C

`(2, oo)`

D

`[4,00)`

Text Solution

Verified by Experts

The correct Answer is:
B

`(dy)/(dx) + (5y)/(x) = 10x^(4) , x > 0`
I.F. `e^(5int1/x dx) = x^5`
Solution is given by `y cdot x^5 = 10 int x^9 dx + c = x^(10) + c`
`y = x^5 + c/(x^5) = y(x)`
At `x = 1, y = 2 implies c = 1`
`y = x^5 + 1/(x^5) in [2, oo)" "("Using" AM ge GM)`.
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