An aircraft executes a horizontal loop of radius 1 km with a steady speed of `900 km h^(-1)`. Compare its centripetal acceleration with the acceleration due to gravity.

Explanation

Here `r=1km = 10^(3)m, v=900kmh^(-1)= 900 xx 5/18= 250ms^(-1)`
Centripetal acceleration = `a_(c) = v^(2)/r=(250)^(2)/(10^(3)) = 62.5 ms^(-2)`
Now, `a_(c)/g=62.5/9.8 = 6.38`