Two absolute scales `A` and `B` have triple points of water defined to be `200A` and `350B`. What is the relation between `T_(A)` and `T_(B)`?

Explanation

Triple point of water on absolute scaleA, `T_(1)` = 200 A
Triple point of water on absolute scale B, `T_(2)` = 350 B
Triple point of water on Kelvin scale, `T_(K)` = 273.15 K
The temperature 273.15 K on Kelvin scale is equivalent to 200 A on absolute scale A.
`T_(1)=T_(K)`
`200A=273.15 K`
`:.A=(273.15)/(200)`
The temperature 273.15 K on Kelvin scale is equivalent to 350 B on absolute scale B.
`T_(2)=T_(K)`
350 B + 273.15
`:.B=(273.15)/(350)`
`T_(A)` is triple point of water on scale A.
`T_(B)` is triple point of water on scale B.
`:.(273.15)/(200)xxT_(A)=(273.15)/(350)xxT_(B)`
`T_(A)=(200)/(350)T_(B)`
Therefore, the ratio `T_(A) : T_(B)` is given as 4 : 7.