The resistance of a platinum wire of platinum resistance thermometer at the ice point is `5 Omega` and at steam point is `5.23 Omega`. When therometer is insertes in a hot bath, the resistance of the platinum wire is `5.795 Omega`. Calculate the temperature of the bath?

Explanation

`R_(0)=5Omega,R_(100)=5.23 Omegaand R_(t)=5.795Omega`
Now, `t=(R_(t)-R_(0))/(R_(100)-R_(0))xx100,R_(t)=R_(0)(1+alphat)`
`=(5.795-5)/(5.23-5)xx100`
`=(0.795)/(0.23)xx100=345.65.^(@)C`.