A solenoid of length `0*5m` has a radius of `1cm` and is made up of `500` turns. It carries a current of `5A`. What is the magnitude of the magnetic field inside the solenoid?

Explanation

The number of turns per unit length is,
`n = (500)/(0.5) = 1000` turns/m
The length `l = 0.5m` and radius `r = 0.01m`. Thus `l//a = 50` i.e., `l gt gt a`. Hence, we can use the long solenoid formula, namely, Eq
`B = mu_(0) nI`
`=4pi xx 10^(-7) xx 10^(3) xx 5`
`= 6.28 xx 10^(-3)T`