What is the magnitude of the equatorial and axial fields due to a bar manget of length `5*0cm` at a distance of `50cm` from its mid-point? The magnetic moment of the bar magnet is `0*40Am^2`.

Explanation

From Eq. (5.7)
`B_(E)=(mu_(0)m)/(4pir^(3))=(10^(-7)xx0.4)/((0.5)^(3))=(10^(-7)xx0.4)/(0.125)=3.2xx10^(-7)T`
From Eq. (5.8). ` B_(A)=(mu_(0)2m)/(4pir^(3))=6.4xx10^(-7)T`