A horizontal straight wire 10 m long extending from east to west falling with a speed of 0.5 `ms^(-1)` at right angles to the horizontal component of the earth's magnetic field `0.30 xx 10^(-4)Wb m^(-2)`
(a) What is the instantaneous value of the e.m.f. induced in the wire ?
(b) What is the direction of the e.m.f.
(c) Which end of the wire is at higher electric potential ?

Explanation

Length of the wire, l = 10 m
Falling speed of the wire, v = 5.0 m/s
Magnetic field strength, B =` 0.3 x× 10^(−4) Wb m^(−2)`
(a) Emf induced in the wire,
e = Blv
`=0.3xx10^(-4)xx5xx10`
`=1.5xx10^(-3)` V
(b) Using Fleming’s right hand rule, it can be inferred that the direction of the induced emf is from West to East.
(c) The eastern end of the wire is at a higher potential.