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Suppose a pure Si-crystal has 5xx10^(28)...

Suppose a pure Si-crystal has `5xx10^(28) "atoms" m^(-3)`. It is doped by 1 ppm concentration of pentavalent As. Calculate the number of electrons and holes. Give that `n_(i)=1.5xx10^(16)m^(-3)`.

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Note that thermally generated electrons `(n_(i) ~10^(16) m^(–3))` are negligibly small as compared to those produced by doping.
Therefore, `n_(e)approxN_(D)`.
Since `n_(e)n_(h) = n_(i)^(2)`, The number of holes
`n_(h) = (2.25 × 10^(32))//(5 ×10^(22))
~ 4.5 × 10^(9) m^(–3)`
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