What should be the width of each slit to obtain `10` maxima of the double slit interference pattern within the central maximum of single slit diffraction pattern ? (NCERT Solved example)

Explanation

We want `atheta=lambda,theta=(lambda)/(a)`
`10 (lambda)/(d)=2(lambda)/(a)a=(d)/(5)=0.2 nm`
Notice that the wavelength of light and distance of the screen do not enter in the calculation of a.