In double slit experiment using light of wavelength `600 nm`, the angular width of a fringe formed on a distant screen is `0.1^(@)`. What is the spacing between the two slits ?

Explanation

Wavelength of light used, `lambda=6000 nm =600 xx10^(-9)`
Angular width of fringe, `theta=0.1^(@)=0.1xx(pi)/(180)=(3.14)/(1800)"rad"`
Angular width of a fringe is related to slit spacing (d) as :
`theta=(lambda)/(d)`
`d=(lambda)/(theta)`
`=(600xx10^(-9))/((3.14)/(1800))=3.44xx10^(-4)m`
Therefore, the spacing between the slits is `3.44xx10^(-4)m.`