The electrostatic force on a small sphere of charge `0.4 muC` due to another small sphere of charge `-0.8 mu C` in air 0.2 N (i) What is the distance between the two spheres? (ii) What is the force on the second sphere due to the first ?

Options

A. The distance between the two spheres is 0.12 m. `0.2 N`
B. The distance between the two spheres is 0.12 m. `1.2 N`
C. The distance between the two spheres is 0.12 m. `2.2 N`
D. The distance between the two spheres is 0.22 m. `22.2 N`

Answer

A

Explanation

(a) Electrostatic force on the first sphere, F = 0.2 N
Charge on this sphere, `q_(1) = 0.4 muC = 0.4 × 10^(−6) C`
Charge on the second sphere, `q_(2) = − 0.8 muC = − 0.8 × 10^(−6) C`
Electrostatic force between the spheres is given by the relation,
`F=(q_(1)q_(2))/(4piepsilon_(0)r^(2)) And, (1)/(4 pi epsilon_(0)) = 9 xx10^(9) N m^(2) C^(-2)`
Where, `epsilon_(0)` = Permittivity of free space
`r^(2) = q1q24 pi epsilon0 F" "= 9 xx109 xx0.4 xx10-6 xx 0.8 xx 10-60.2" "=144 xx 10-` `4r = 144 xx 10-4 = 0.12m`
The distance between the two spheres is 0.12 m.
(b) Both the spheres attract each other with the same force. Therefore, the force on the second sphere due to the first is 0.2 N.