If `(1-y)(1+2x+4x^2+8x^3+16x^4+32x^5)=(1-y^6)` then `y/x`=

If (1 - y) (1 + 2x + 4x^(2) + 8x^(3) + 16x^(4) + 32x^(5) ) = 1 -y^(6), (y ne 1) , then a value of y/x is

The HCF of 8x^(4) - 16x^(3) - 40x^(2) + 48x and 16x^(5) + 64x^(4) + 80x^(3) + 32x^(2) is

Divide 14x^3y^3+8x^2y^3-32x^5y^5 by -2xy^3

If Delta(x)=|(x^2+4x-3, 2x+4, 13), (2x^2+5x-9, 4x+5, 26), (8x^2-6x+1, 16x-6, 104)|=a x^3+b x^2+c x+d , then

2x +y ge 4 ,x+ y le 3,2x - 3y le 6

The equation of the circle having the intercept on the line y+2x=0 by the circle x^2 + y^2 + 4x + 6y = 0 as a diameter is : (A) 5x^2 + 5y^2 - 8x + 16y =0 (B) 5x^2 + 5y^2 + 8x - 16y =0 (C) 5x^2 + 5y^2 - 8x - 16y =0 (D) 5x^2 + 5y^2 + 8x+- 16y =0

The equation of the circle having the intercept on the line y+2x=0 by the circle x^2 + y^2 + 4x + 6y = 0 as a diameter is : (A) 5x^2 + 5y^2 - 8x + 16y =0 (B) 5x^2 + 5y^2 + 8x - 16y =0 (C) 5x^2 + 5y^2 - 8x - 16y =0 (D) 5x^2 + 5y^2 + 8x+- 16y =0