If the lines `p_1x+q_1y=1,p_2x+q_2y=1a n dp_3x+q_3y=1,` be concurrent, show that the point `(p_1, q_1),(p_2, q_2)a n d(p_3, q_3)` are collinear.

Explanation

Given:

`p_1​x+q_1​y=1,p_2​x+q_2​y=1 and p_3​x+q_3​y=1`


The lines will be concurrent if
`=>|[p_1,q_1,-1],[p_2,q_2,-1],[p_3,q_3,-1]|=0`

`=>1/2|[p_1,q_1,1],[p_2,q_2,1],[p_3,q_3,1]|=0`

`=>triangle=0`


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