`int tan (2 theta)/ sqrt(sin^6 theta+ cos^6 theta) d theta`

int (sin theta + cos theta) * d theta

int(tan2 theta)/(sqrt(cos^(6)theta+sin^(6)theta))d(theta)

int((sin theta-cos theta)d theta)/((sin theta+cos theta)sqrt(sin^(2) theta cos^(2)theta+sin theta cos theta))

Solve int((sin theta+sqrt(cos^(2)theta+2sin^(2)theta))^(n))/(sqrt(1+sin^(2)theta))cos theta d theta , where n ne -1 .

int (d theta)/((sin theta - 2 cos theta)(2 sin theta + cos theta))

int (d theta)/((sin theta - 2 cos theta)(2 sin theta + cos theta))

int _(0)^(pi//2) (2sqrt(cos theta))/(3(sqrt(sin theta )+ sqrt(cos theta ))) d theta is equal to

int(2sin theta cos theta)/(sin^(4)theta+cos^(4)theta)d theta

int (sin theta cos theta) / (cos ^ (2) theta-cos theta-2) d theta