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A line 4x+y=1 passes through the point A...

A line `4x+y=1` passes through the point A(2,-7) and meets line BC at B whose equation is `3x -4y +1=0`, the equation of line AC such that `AB=AC` is (a) 52x +89y +519=0(b) 52x +89y-519=0 c) 82x +52y+519=0 (d) 89x +52y -519=0

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Let `AB` makes an angle α with `BC.`

Given` AB = AC`

So` ∠ABC = ∠ACB`

Equation of `BC` is `3x – 4y + 1 = 0`

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