One side of a rectangle lies along the line `4x+7y+5=0.` Two of its vertices are `(-3,1)a n d(1,1)dot` Find the equations of the other three sides.

Explanation

Since, the side `{AB}` is perpendicular to `{AD}`


`therefore` Its equation if of the form `7 {x}-4 {y}+lambda=0`


Since, it passes through `(-3,1)`


`therefore 7(-3)-4(1)+lambda=0 rightarrow lambda=25`


`therefore` Equation of `{AB}` is `7 {x}-4 {y}+25=0`


Now, `{BC}` is parallel to `{AD}`


Therefore, its equation is `4 {x}+7 {y}+lambda=0`


Since, it passes through `(1,1)`.


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