|[1+a^(2)-b^(2)],[2ab],[2b]

The value of the determinant |{:(1+ a^(2) - b^(2),2 ab , - 2b),(2ab, 1 - a^(2) + b^(2), 2a),(2b , -2a , 1-a^(2) - b^(2)):}| is equal to

By using properties of determinants , show that : {:[( 1+a^(2) -b^(2) ,2ab , -2b),( 2ab, 1-a^(2) +b^(2) , 2a),( 2b, -2a, 1-a^(2) -b^(2)) ]:}=( 1+a^(2) +b^(2)) ^(3)

Using the properties of determinants, show that abs[[1+a^2-b^2,2ab,-2b],[2ab,1-a^2+b^2,2a],[2b,-2a,1-a^2-b^2]]=(1+a^2+b^2)^3

1+a^(2)-b^(2),2ab,-2b2ab,1-a^(2)+b^(2),2a2b,-2a,1-a^(2)-b^(2)]|=(1+a^(2)+b^(2))^(3)

Answer any three questions Using properties of determinants, prove the following abs{:(1+a^2 - b^2,2ab,-2b),(2ab,1-a^(2) +b^(2) ,2a),(2b,-2a,1-a^2 -b^2):}=(1+a^2 +b^2)^3.

prove that |[a,b,0],[0,a,b],[b,0,a]|=a^3+b^3,hence find the value of |[2ab,a^2,b^2],[a^2,b^2,2ab],[b^2,2ab,a^2]|

Simplify: a^(2)b(a-b^(2))+ab^(2)(4ab-2a^(2))-a^(3)b(1-2b)

Prove that |(2ab,a^(2),b^(2)),(a^(2),b^(2),2ab),(b^(2),2ab,a^(2))|=-(a^(3)+b^(3))^(2) .

Prove that |[2ab,a^2,b^2],[a^2,b^2,2ab],[b^2,2ab,a^2]|=-(a^3+b^3)^2 .