" Let "f(x,n)=sum_(k=1)^(n)log_(x)((k)/(X))" .Then the value of "x" satisfying the equation "f(x,10)=f(x,11)" is "

Suppose,f(x,n)=sum_(k=1)^(n)log_(x)((k)/(x)), then the value ofx satisfying the equation f(x,10)=f(x,11), is

Let f(x,k)=sum_(n=1)^(k)log_(x)((n)/(x)), then value of ? which is satisfying the equation f(x,2017)=f(x,2018) is

Let f(x)=(kx)/(x+1) then the value of k such that f(x) is

The natural number a for which sum_(k=1)^(n)f(a+k)=2n(33+n) where the function f satisfies the relation f(x+y)=f(x)+f(y) for all the natural numbers x,y and further f(1)=4 is

Find the natural number a for which sum_(k=1) ^(n)f(a+k)= 16(2^(n)-1) where the function f satisfies the relation f(x+y)=f(x)f(y) for all natural numbers x,y and further f(1)=2 .

Find the natural number a for which sum_(k=1)^(n)f(a+k)=16(2^(n)-1), where the function f satisfies the relation f(x+y)=f(x)f(y) for all natural number x,y and,further,f(1)=2.

The natural number a for which sum_(k=1)^(n)f(a+k)=16(2^(n)-1) where the function f satisfies the relation f(x+y)=f(x)*f(y) for all natural numbers x,y and further f(1)=2 is

The value of natural number 'a' for which sum_(k=1)^(n)f(a+k)=16(2^(n)-1) , where the function satisfies the relation f(x+y)=f(x).f(y) for all natural numbers x, y and further f(1)=2 is

f(x) = log((1+x)/(1-x)) satisfies the equation: f(x_(1)) +f(x_(2))

If f(x)=sum_(n=0)^(oo)(x^(n))/(n!)(log a)^(n), then at x=0,f(x)