Find the slope of the lines which make an angle of `45^0` with the line `3x-y+5=0.`

Explanation

equation of the line is
`3x-y+5=0 y=3x+5,m_1=3`


Angle between the two lines `theta=45`


`tan^-1 |(m_1-m_2)/(1+m_1m_2)|=>(m_1-m_2)/(1+m_1m_2)=45^@`


`(3-m_2)/(1+3m_2)=1`

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