[" For the circle "ax^(2)+y^(2)+bx+dy+2],[" centre is "(1,2)" then "2b+3d=]

For the circle ax^(2)+y^(2)+bx+dy+2=0 centre is (1,2) then 2b+3d =

For the circle ax^(2)+y^(2)+bx+dy+2=0 centre is (1,2) then 2b+3d=

For the circle ax^(2)+y^(2)+bx+dy+2=0 centre is (1,2) then 2b+3d=

If the circle x^(2) + y ^(2) + ax + by - 12=0 has the centre at (2,3) then find a, b and the radius of the circle .

If the circle x^(2)+y^(2)+ax+by-12=0 has the centre at (2,3) then find a, b, and the radius of the circle.

The coordinates of the centre of the circle 2x^(2)+2y^(2) + ax + by + c= 0 are (3, - 4), find a and b.

If a circle passes through the point (a, b) and cuts the circle x^2 + y^2 = 4 orthogonally, then the locus of its centre is (a) 2ax+2by-(a^(2)+b^(2)+4)=0 (b) 2ax+2by-(a^(2)-b^(2)+k^(2))=0 (c) x^(2)+y^(2)-3ax-4by+(a^(2)+b^(2)-k^(2))=0 (d) x^(2)+y^(2)-2ax-3by+(a^(2)-b^(2)-k^(2))=0

If the expression ax^(3) + 2x^(2) y - bx y^(2) -2y^(3) is symmetric, then (a,b) =

The curve y=ax^2+bx has minimum at (2,-12) on it. Then (a,b) =

If (x,3) and (3,5) are the extremities of a diameter of a circle with centre at (2,y) then the values of x and y are a.(3,1) b.x=4,y=1 c.x=8,y=2d .none of these