Find the ratio in which the line `3x+4y+2=0` divides the distance between the lines `3x+4y+5=0a n d3x+4y-5=0.`

Explanation

Line `3x+4y+2=0 & 3x+4y+5=0` are on the same side of the origin. The distance between these lines are


`d_1=|(2-5)/sqrt(3^2+4^2)=3/5`


Lines `3x+4y+2=0` and `3x+4y-5+0` are on the opposite side of the origin. The distance between these lines is


`d_2=|(2+5)/sqrt(3^2+4^2)=7/5`


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