AB and CD are towers of height `h_1` and `h_2` respectively having feet A and C on same level. AD and BC intersects at P. If distance between tower is geometric mean of `h_1` and `h_2` then locus of P is:

If two towers of height h_(1) and h_(2) subted angle of 60^(@) and 30^(@) respectively at the mid point of the line joining their feet, then find h_(1):h_(2) .

If two towers of heights h_(1) and h_(2) subtend angles 60^(o) and 30^(circ) respectively at the mid poind of the line joining their feet then h_(1): h_(2^(*))

From the top of a tower, the angles of depression of two objects on the same side of the tower are found to be alpha and beta(alpha gt beta) .If the distance between the objects is p metres, show that the height h of the tower is given by h=(p tan alpha tan beta)/(tan alpha - tan beta) metres.

From the top of a tower, the angles of depression of two objects on the same side of the tower are found to be alpha and beta (alpha >beta) . If the distance between the objects is 'p' metres, show that the height 'h' of the tower is given by h=frac(p tan alpha tan beta)(tan alpha-tan beta) also determine the height of the tower, if p=50 m , alpha=60^@, beta=30^@

The heights of two towers are h_1 metre and h_2 metre. If the angle of elevation of the top of the first tower from the foot of the 2nd tower is 60^@ and the angle of elevation of the 2nd tower from the foot of the 1st tower is 45% then prove that h_1^2= 3h_2^2 .

The foot of a tower of height h m is in a direct line between two observers A and B. If the angles of elevationof the top of the tower as seenfrom and B are alpha and beta respectively and if AB = d m, then what is h/d equal to?