|[0,p-q,p-r],[q-p,0,q-r],[r-p,r-q,0]|=

Choose the correct answer from the bracket.The value of the determinant abs[[0,p-q,p-r],[q-p,0,q-r],[r-p,r-q,0]] is

Select and write the correct answer from the given alternatives in each of the following: |(0,p-q,q-r),(q-p,0,q-r),(r-p,r-q,0)| is equal to

Let A=[[0,2q,r] , [p,q,-r] , [p,-q,r]] If A A^T=I_3 then |p|=

Let A=[[0,2q,r] , [p,q,-r] , [p,-q,r]] If A A^T=I_3 then |p|=

Let A=[[0,2q,r] , [p,q,-r] , [p,-q,r]] If A A^T=I_3 then |p|=

Let A=[[0,2q,r] , [p,q,-r] , [p,-q,r]] If A A^T=I_3 then |p|=

Show that: |[p-q-r,2p,2p],[2q,q-r-p,2q],[2r,2r,r-p-q]|=(p+q+r)^3

Let A=|{:(,0,21,r),(,p,q,-r),(,p,-q,r):}|=A A^(T)=I_(3) then |p| is

p,q,q,r Show that ,q,p,,q,r,r,p,r,q